From 6.55 g of aniline, the maximum amount of acetanilide that can be prepared will be _____

From 6.55 g of Aniline Maximum Acetanilide | JEE Mains PYQ

Q. From 6.55 g of aniline, the maximum amount of acetanilide that can be prepared will be ______ × 10⁻¹ g.

Step 1: Write the reaction

Aniline reacts with acetic anhydride to form acetanilide. The mole ratio of aniline to acetanilide is 1 : 1.

Step 2: Calculate moles of aniline

Molar mass of aniline (C₆H₅NH₂) = 93 g mol⁻¹ Moles of aniline = 6.55 / 93 = 0.0704 mol

Step 3: Calculate mass of acetanilide formed

Molar mass of acetanilide = 135 g mol⁻¹ Mass = 0.0704 × 135 = 9.5 g

Step 4: Express in required form

9.5 g = 95 × 10⁻¹ g

Final Answer: 95