q34

Molarity of NaCl Solution | JEE Mains PYQ

Q. The Molarity (M) of an aqueous solution containing 5.85 g of NaCl in 500 mL water is : (Given : Molar Mass Na : 23 and Cl : 35.5 g mol⁻¹)

Step 1: Calculate molar mass of NaCl

Molar mass of NaCl = 23 + 35.5 = 58.5 g mol⁻¹

Step 2: Calculate number of moles of NaCl

Moles of NaCl = 5.85 / 58.5 = 0.1 mol

Step 3: Convert volume into liters

500 mL = 0.5 L

Step 4: Calculate molarity

Molarity = moles / volume = 0.1 / 0.5 = 0.2 M

Final Answer: 0.2

Previous Year Questions

X g of ethylamine is subjected to reaction with NaNO₂/HCl followed by water; evolved dinitrogen gas which occupied 2.24 L volume at STP.

X g of ethylamine reacts with NaNO₂/HCl followed by water; evolved dinitrogen gas which occupied 2.24 L volume at STP.

From 6.55 g of aniline, the maximum amount of acetanilide that can be prepared will be ______ × 10⁻¹ g.

Molality of an aqueous solution of urea is 4.44 m. Mole fraction of urea in solution is x × 10⁻³.

Combustion of glucose (C₆H₁₂O₆) produces CO₂ and water. The amount of oxygen required for the complete combustion of 900 g of glucose is :

JEE Mains Full Study Material

Updated for JEE Main 2026: This PYQ is important for JEE Mains, JEE Advanced and other competitive exams. Practice more questions from this chapter.