Number of moles of methane required to produce 22 g CO₂(g) after combustion is x × 10⁻² moles. The value of x is ______.

Methane Combustion Numerical | JEE Mains PYQ | Mole Concept

Q. Number of moles of methane required to produce 22 g CO₂(g) after combustion is x × 10⁻² moles. The value of x is ______.

Explanation

Step 1: Write balanced chemical equation

CH₄(g) + 2O₂(g) → CO₂(g) + 2H₂O(l)

Step 2: Find moles of CO₂ produced

Molar mass of CO₂ = 44 g mol⁻¹
Moles of CO₂ = 22 ÷ 44 = 0.5 mol

Step 3: Mole ratio from balanced equation

1 mole of CH₄ produces 1 mole of CO₂

Step 4: Calculate moles of CH₄ required

Moles of CH₄ required = 0.5 mol

Step 5: Express in x × 10⁻² form

0.5 = 50 × 10⁻²

Correct Answer = 50

Previous Year Questions – Mole Concept

Molar mass of the salt from NaBr, NaNO3, KI and CaF2 which does not evolve coloured vapours on heating with concentrated H2SO4 is ______ g mol−1.

A solution of H2SO4 is 31.4% H2SO4 by mass and has a density of 1.25 g/mL. The molarity of the H2SO4 solution is ______ M (nearest integer).

If 50 mL of 0.5 M oxalic acid is required to neutralise 25 mL of NaOH solution, the amount of NaOH in 50 mL of given NaOH solution is ______ g.

Molality of 0.8 M H2SO4 solution (density 1.06 g cm−3) is ______ × 10−3 m.

If a substance 'A' dissolves in solution of a mixture of 'B' and 'C' with their respective number of moles as nA, nB and nC, mole fraction of C in the solution is

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Updated for JEE Main 2026: This PYQ is important for JEE Mains, JEE Advanced and other competitive exams. Practice more questions from this chapter.