Explanation

When a conductor moves in a magnetic field, the induced EMF is given by

$$ \varepsilon = B \, l \, v $$

Maximum induced EMF occurs when the velocity of the pendulum is maximum, i.e., at the mean position.

Using energy conservation, the maximum speed of the pendulum bob is obtained from

$$ \frac{1}{2}mv^2 = mgL(1-\cos\theta) $$

Here,

$$ L = 0.1\,\text{m}, \quad \theta = 60^\circ $$

$$ 1 - \cos 60^\circ = 1 - \frac{1}{2} = \frac{1}{2} $$

So,

$$ v = \sqrt{2gL \cdot \frac{1}{2}} = \sqrt{gL} $$

$$ v = \sqrt{10 \times 0.1} = 1\,\text{m/s} $$

Now, substituting values in the EMF formula,

$$ \varepsilon_{\max} = B \, l \, v $$

$$ = 2 \times 0.1 \times 1 = 0.2\,\text{V} $$

Since EMF is induced across half the oscillation length effectively contributing,

$$ \varepsilon_{\max} = 0.1\,\text{V} = 100\,\text{mV} $$

Hence, the maximum induced EMF is

$$ \boxed{100} $$

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