Explanation

First, list all possible structural isomers of C₅H₁₁Br.

There are 8 structural isomers of C₅H₁₁Br.

On treatment with KOH(aq), all these undergo nucleophilic substitution to form corresponding alcohols (C₅H₁₁OH).

Now, check each product for the presence of a chiral carbon (carbon attached to four different groups).

After substitution:

• 1-bromopentane → 1-pentanol (no chiral carbon)
• 2-bromopentane → 2-pentanol (one chiral carbon → optically active)
• 3-bromopentane → 3-pentanol (symmetrical → achiral)

From branched chain isomers:

• 2-bromo-2-methylbutane → tert-amyl alcohol (no chiral carbon)
• 1-bromo-3-methylbutane → 3-methyl-1-butanol (no chiral carbon)
• 2-bromo-3-methylbutane → 3-methyl-2-butanol (chiral → optically active)

• 1-bromo-2-methylbutane → 2-methyl-1-butanol (chiral → optically active)

Thus, the optically active alcohols formed are:

1. 2-pentanol
2. 3-methyl-2-butanol
3. 2-methyl-1-butanol

Total number of products showing optical isomerism:

= 3

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