If ε, E and t represent the free space permittivity electric field and time respectively
Q. If $\varepsilon$, $E$ and $t$ represent the free space permittivity, electric field and time respectively, then the unit of $\dfrac{\varepsilon E}{t}$ will be :

(A) A m

(B) A/m

(C) A/m2

(D) A m2

Correct Answer: A/m2

Explanation

Permittivity of free space $\varepsilon_0$ has SI unit

$$ \varepsilon_0 = \frac{\text{C}^2}{\text{N m}^2} $$

Electric field $E$ has SI unit

$$ E = \frac{\text{N}}{\text{C}} $$

Time $t$ has unit second (s).

Now consider the quantity

$$ \frac{\varepsilon E}{t} $$

Substituting units,

$$ \frac{\varepsilon E}{t} = \frac{\dfrac{\text{C}^2}{\text{N m}^2} \times \dfrac{\text{N}}{\text{C}}}{\text{s}} $$

Simplifying,

$$ = \frac{\text{C}}{\text{m}^2 \text{s}} $$

Since

$$ \frac{\text{C}}{\text{s}} = \text{A} $$

Therefore,

$$ \frac{\varepsilon E}{t} = \frac{\text{A}}{\text{m}^2} $$

Hence, the correct unit is

A/m2

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