(A) A m
(B) A/m
(C) A/m2
(D) A m2
Permittivity of free space $\varepsilon_0$ has SI unit
$$ \varepsilon_0 = \frac{\text{C}^2}{\text{N m}^2} $$
Electric field $E$ has SI unit
$$ E = \frac{\text{N}}{\text{C}} $$
Time $t$ has unit second (s).
Now consider the quantity
$$ \frac{\varepsilon E}{t} $$
Substituting units,
$$ \frac{\varepsilon E}{t} = \frac{\dfrac{\text{C}^2}{\text{N m}^2} \times \dfrac{\text{N}}{\text{C}}}{\text{s}} $$
Simplifying,
$$ = \frac{\text{C}}{\text{m}^2 \text{s}} $$
Since
$$ \frac{\text{C}}{\text{s}} = \text{A} $$
Therefore,
$$ \frac{\varepsilon E}{t} = \frac{\text{A}}{\text{m}^2} $$
Hence, the correct unit is
A/m2
Updated for JEE Main 2026: This PYQ is important for JEE Mains, JEE Advanced and other competitive exams. Practice more questions from this chapter.