Fortification of food with iron is done using FeSO₄·7H₂O.
The mass in grams of the FeSO₄·7H₂O required to achieve
12 ppm of iron in 150 kg of wheat is ______ (Nearest integer)
Given: Molar mass of Fe, S and O respectively are
56, 32 and 16 g mol⁻¹
Step 1: Calculate the mass of iron required
12 ppm means 12 mg of iron per kg of wheat.
Step 2: Calculate total iron needed for 150 kg wheat
Iron required = 12 × 150 = 1800 mg = 1.8 g
Step 3: Calculate molar mass of FeSO₄·7H₂O
FeSO₄ = 56 + 32 + (4 × 16) = 152 g mol⁻¹
7H₂O = 7 × 18 = 126 g mol⁻¹
Total molar mass = 152 + 126 = 278 g mol⁻¹
Step 4: Calculate fraction of iron in FeSO₄·7H₂O
Fraction of Fe = 56 / 278
Step 5: Calculate mass of FeSO₄·7H₂O required
Required mass = 1.8 × (278 / 56) ≈ 8.93 g
✅ Final Answer: 9 g