Arrhenius equation is given by:
$$ k = A e^{-E_a/RT} $$
Statement A: The factor $e^{-E_a/RT}$ represents the fraction of molecules having kinetic energy greater than or equal to activation energy $E_a$, not less. Hence, statement A is incorrect.
Statement B: At a fixed temperature, a lower activation energy $E_a$ means a larger fraction of molecules can cross the energy barrier, resulting in a faster reaction. Hence, statement B is correct.
Statement C: Empirically, for many reactions, an increase in temperature by about $10^\circ$C approximately doubles the reaction rate. Hence, statement C is correct.
Statement D: From Arrhenius equation:
$$ \log k = \log A - \frac{E_a}{2.303R}\left(\frac{1}{T}\right) $$
So, slope of $\log k$ vs $\dfrac{1}{T}$ is $-\dfrac{E_a}{2.303R}$, not $-\dfrac{E_a}{R}$. Hence, statement D is incorrect.
Therefore, the correct statements are:
B and C only
Updated for JEE Main 2026: This PYQ is important for JEE Mains, JEE Advanced and other competitive exams. Practice more questions from this chapter.