(Bohr's radius is represented by a0)
For 1s orbital, probability density is maximum at the nucleus. Hence, statement A is correct.
Electron in 1s orbital has a finite probability of being found at distances greater than a0, including 2a0. So, statement C is correct.
The total energy of the electron in a given orbital is fixed and does not depend on its distance from the nucleus.
Hence, statement B is incorrect.
Correct Answer = B
Updated for JEE Main 2026: This PYQ is important for JEE Mains, JEE Advanced and other competitive exams. Practice more questions from this chapter.