The halogen that makes longest bond with hydrogen in HX and group 15 hydride EH3 statement based question
Q. Given below are two statements :

Statement I : The halogen that makes longest bond with hydrogen in HX, has the smallest covalent radius in its group.

Statement II : A group 15 element's hydride EH3 has the lowest boiling point among corresponding hydrides of other group 15 elements. The maximum covalency of that element E is 4.

In the light of the above statements, choose the correct answer from the options given below.
A. Statement I is true but Statement II is false
B. Statement I is false but Statement II is true
C. Both Statement I and Statement II are true
D. Both Statement I and Statement II are false
Correct Answer: Both Statement I and Statement II are false

Explanation

Statement I analysis:

Hydrogen halides are: HF, HCl, HBr and HI.

Bond length in HX increases down the group because atomic size of halogen increases:
HF < HCl < HBr < HI

So, the longest H–X bond is in HI.

But iodine has the largest covalent radius, not the smallest.

Hence, Statement I is false.


Statement II analysis:

Group 15 hydrides are:
NH3, PH3, AsH3, SbH3, BiH3

Among these, PH3 has the lowest boiling point because:

NH3 shows hydrogen bonding → higher boiling point.
Heavier hydrides have higher boiling points due to stronger van der Waals forces.

So element E = Phosphorus.

Maximum covalency of phosphorus is 5 (for example, PCl5).

But statement says maximum covalency is 4, which is incorrect.

Hence, Statement II is false.

Therefore, both Statement I and Statement II are false.

This type of statement-based reasoning question is very important for JEE Main, JEE Advanced and IIT JEE.

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