Keeping the significant figures in view, the sum of the physical quantities 52.01 m, 153.2 m and 0.123 m is :

Keeping the significant figures in view, the sum of the physical quantities 52.01 m, 153.2 m and 0.123 m is :

Q. Keeping the significant figures in view, the sum of the physical quantities 52.01 m, 153.2 m and 0.123 m is :

A. 205.3 m

B. 205 m

C. 205.333 m

D. 205.33 m

Correct Answer: 205.3 m

Step 1: Perform Normal Addition

52.01 + 153.2 + 0.123

52.01
153.2
0.123
———————

= 205.333 m

Step 2: Apply Significant Figure Rule for Addition

In addition and subtraction, the result must be rounded to the least number of decimal places present in the given data.

52.01 → 2 decimal places
153.2 → 1 decimal place ❗ (least)
0.123 → 3 decimal places

Therefore, final answer must be rounded to 1 decimal place.

Step 3: Rounding

205.333 rounded to 1 decimal place = 205.3 m

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jee mains jee advanced neet physics units and measurements significant figures rounding off rules precision and accuracy error analysis measurement errors iit jee physics physics numericals addition rule sig figs

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