The energy of an electron in the first Bohr orbit of the H-atom is −13.6 eV. The magnitude of energy value of an electron in the first excited state of

Energy of Electron in Be³⁺ Ion | JEE Mains PYQ | Structure of Atom

Q. The energy of an electron in the first Bohr orbit of the H-atom is −13.6 eV. The magnitude of energy value of an electron in the first excited state of Be³⁺ is ______ eV (nearest integer value).

Explanation

Step 1: Energy formula for hydrogen-like species

E_n = −13.6 × Z² / n² (in eV)

Step 2: Values for Be³⁺

Atomic number Z = 4
First excited state ⇒ n = 2

Step 3: Substitute values

E = −13.6 × (4)² / (2)²
E = −13.6 × 16 / 4
E = −13.6 × 4 = −54.4 eV

Step 4: Take magnitude and nearest integer

|E| ≈ 54 eV

Correct Answer = 54

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