Frequency of de-Broglie Wave in First Bohr Orbit | JEE Mains PYQ | Structure of Atom
Q. Frequency of the de-Broglie wave of electron in Bohr's first orbit of hydrogen atom is ______ × 10¹³ Hz (nearest integer).

Given:
RH (Rydberg constant) = 2.18 × 10−18 J
h (Planck's constant) = 6.6 × 10−34 J·s

Solution
Step 1: Energy of electron in first Bohr orbit

Energy of electron in nth orbit:
En = − RH / n²

For first orbit (n = 1):
E₁ = − 2.18 × 10−18 J

Step 2: Relation between energy and frequency

Energy of matter wave:
E = hν

⇒ ν = |E| / h

Step 3: Substitute values

ν = (2.18 × 10−18) / (6.6 × 10−34)

ν ≈ 0.33 × 1016 Hz
ν ≈ 3.3 × 1015 Hz

Step 4: Convert into required format

3.3 × 1015 Hz = 330 × 1013 Hz

Final Answer = 330

Updated for JEE Main 2026: This PYQ is important for JEE Mains, JEE Advanced and other competitive exams. Practice more questions from this chapter.

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