(A) n = 4, l = 1

(B) n = 4, l = 2

(C) n = 3, l = 1

(D) n = 3, l = 2

(E) n = 4, l = 0

Choose the correct answer from the options given below:

For multielectron atoms, energy increases with increasing value of (n + l).
If (n + l) is same, orbital with higher n has higher energy.

(C): n + l = 3 + 1 = 4
(E): n + l = 4 + 0 = 4
(D): n + l = 3 + 2 = 5
(A): n + l = 4 + 1 = 5
(B): n + l = 4 + 2 = 6

For same (n + l): lower n → lower energy

Correct order: (C) < (E) < (D) < (A) < (B)