Correct Answer: 494 kJ mol⁻¹
Energy of one photon:
E = hc / λ
E = (6.626 × 10⁻³⁴ × 3 × 10⁸) / (242 × 10⁻⁹)
E ≈ 8.21 × 10⁻¹⁹ J per atom
Ionization energy per mole:
E = 8.21 × 10⁻¹⁹ × 6.022 × 10²³
E ≈ 4.94 × 10⁵ J mol⁻¹ = 494 kJ mol⁻¹
Updated for JEE Main 2026: This PYQ is important for JEE Mains, JEE Advanced and other competitive exams. Practice more questions from this chapter.