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Carbon Percentage Numerical – JEE Main PYQs | Combustion Analysis Chemistry

An organic compound weighing 500 mg produced 220 mg of CO₂ on complete combustion. The percentage composition of carbon in the compound is ______ %. (Nearest integer)

Given: Molar mass (in g mol⁻¹) of C = 12, O = 16

Step 1: Convert mass of CO₂ into grams

220 mg = 0.220 g

Step 2: Calculate moles of CO₂ formed

Moles of CO₂ = 0.220 / 44 = 0.005 moles

Step 3: Calculate moles of carbon present

1 mole of CO₂ contains 1 mole of carbon.
Moles of carbon = 0.005 moles

Step 4: Calculate mass of carbon

Mass of carbon = 0.005 × 12 = 0.06 g = 60 mg

Step 5: Calculate percentage of carbon

Percentage of carbon = (60 / 500) × 100 = 12%

✅ Final Answer: 12%

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