QInteger TypeCoordination Compounds
Number of paramagnetic complexes among the following is __________.

[MnBr₄]²⁻,  [NiCl₄]²⁻,  [Ni(CN)₄]²⁻,  [Ni(CO)₄],  [CoF₆]³⁻,
[Fe(CN)₆]⁴⁻,  [Mn(CN)₆]³⁻,  [Ti(CN)₆]³⁻,  [Cu(H₂O)₆]²⁺,  [Co(C₂O₄)₃]³⁻
✅ Correct Answer
7
Solution
1
Identify metal ion oxidation state and d-electron count
[MnBr₄]²⁻ : Mn²⁺, d⁵ — Br⁻ is weak field → high spin → 5 unpaired → Paramagnetic
[NiCl₄]²⁻ : Ni²⁺, d⁸ — Cl⁻ weak, tetrahedral → 2 unpaired → Paramagnetic
[Ni(CN)₄]²⁻: Ni²⁺, d⁸ — CN⁻ strong field → square planar → 0 unpaired → Diamagnetic
[Ni(CO)₄] : Ni⁰, d¹⁰ → 0 unpaired → Diamagnetic
[CoF₆]³⁻ : Co³⁺, d⁶ — F⁻ weak field → high spin → 4 unpaired → Paramagnetic
[Fe(CN)₆]⁴⁻: Fe²⁺, d⁶ — CN⁻ strong → low spin → 0 unpaired → Diamagnetic
[Mn(CN)₆]³⁻: Mn³⁺, d⁴ — CN⁻ strong → low spin → 2 unpaired → Paramagnetic
[Ti(CN)₆]³⁻: Ti³⁺, d¹ → 1 unpaired → Paramagnetic
[Cu(H₂O)₆]²⁺: Cu²⁺, d⁹ → 1 unpaired → Paramagnetic
[Co(C₂O₄)₃]³⁻: Co³⁺, d⁶ — oxalate moderate field → high spin → 4 unpaired → Paramagnetic
2
Count paramagnetic complexes
Paramagnetic (unpaired electrons): MnBr₄²⁻, NiCl₄²⁻, CoF₆³⁻, Mn(CN)₆³⁻, Ti(CN)₆³⁻, Cu(H₂O)₆²⁺, Co(C₂O₄)₃³⁻

Diamagnetic: Ni(CN)₄²⁻, Ni(CO)₄, Fe(CN)₆⁴⁻

$$\text{Number of paramagnetic complexes} = \boxed{7}$$
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Theory & Key Concepts
Paramagnetism and Crystal Field Theory

Paramagnetic substances have one or more unpaired electrons and are weakly attracted to a magnetic field. Diamagnetic substances have all electrons paired and are weakly repelled by a magnetic field.

Strong field vs weak field ligands (spectrochemical series, partial list):
I⁻ < Br⁻ < Cl⁻ < F⁻ < OH⁻ < ox²⁻ < H₂O < NH₃ < en < CN⁻ < CO

High spin vs low spin for d⁶ (Co³⁺, Fe²⁺): With weak field ligands (F⁻, ox²⁻): high spin, 4 unpaired electrons. With strong field ligands (CN⁻): low spin, 0 unpaired electrons. The crossover depends on whether CFSE exceeds pairing energy.

Geometry rules: Strong field + Ni²⁺ (d⁸) → square planar (Ni(CN)₄²⁻) → diamagnetic. Weak field + Ni²⁺ → tetrahedral (NiCl₄²⁻) → paramagnetic (2 unpaired). Ni(CO)₄ is Ni⁰ with d¹⁰ → always diamagnetic.

Key d-electron counts: d⁰ and d¹⁰ are always diamagnetic (no unpaired) or always have n unpaired respectively. d¹⁰ = 0 unpaired. d⁵ high spin = 5 unpaired (maximum).

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Important Concepts
Spectrochemical Series

Ligands ordered by field strength: I⁻ < Br⁻ < Cl⁻ < F⁻ < OH⁻ < ox < H₂O < NH₃ < en < CN⁻ < CO. Weak field → high spin (more unpaired). Strong field → low spin (fewer unpaired). Memorising this series is essential.

d-Electron Count Rule

For d⁶ metal with weak ligand: 4 unpaired (high spin). With strong ligand: 0 unpaired (low spin). For d⁸ Ni²⁺: tetrahedral (weak) = 2 unpaired; square planar (strong) = 0 unpaired. For d¹⁰ (Ni⁰ in Ni(CO)₄): 0 unpaired, always diamagnetic.

Oxalate as Ligand

Oxalate (C₂O₄²⁻) is a moderate field ligand — weaker than CN⁻ but stronger than halides. Co³⁺ (d⁶) with oxalate is high spin → 4 unpaired → paramagnetic. Compare: [Co(CN)₆]³⁻ would be low spin → 0 unpaired.

Mn³⁺ d⁴ with CN⁻ (Strong Field)

Low spin Mn³⁺ d⁴: electrons fill t₂g as: t₂g⁴ eg⁰. With strong CN⁻, pairing occurs in t₂g → 2 unpaired electrons (t₂g has 3 orbitals, 4 electrons → one orbital has 2, two orbitals have 1 each = 2 unpaired). Paramagnetic.

FAQs
1
How to determine high spin vs low spin?
Compare the ligand field splitting energy (Δ) with the pairing energy (P). If Δ > P → low spin (strong field ligand). If Δ < P → high spin (weak field ligand). CN⁻ and CO always give low spin; F⁻, Cl⁻, Br⁻ give high spin.
2
Why is Ni(CO)₄ diamagnetic?
CO is the strongest field ligand and causes Ni to adopt Ni⁰ oxidation state with d¹⁰ configuration. All 10 d-electrons are paired → 0 unpaired electrons → diamagnetic.
3
Why is [CoF₆]³⁻ paramagnetic?
Co³⁺ is d⁶. F⁻ is a weak field ligand. High spin d⁶: electrons fill as t₂g⁴ eg² → 4 unpaired electrons → strongly paramagnetic.
4
What about [Ti(CN)₆]³⁻?
Ti³⁺ is d¹. Only one d-electron, always 1 unpaired regardless of ligand field strength. Always paramagnetic.
5
Is this from JEE Main 2026?
Yes, this appeared in JEE Main 2026 Chemistry Section B.
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