The speed of electromagnetic waves in a medium is given by
$$ v = \frac{1}{\sqrt{\mu \epsilon}} $$
For vacuum,
$$ v_0 = \frac{1}{\sqrt{\mu_0 \epsilon_0}} $$
For the given medium, dielectric constant $k = \dfrac{\epsilon}{\epsilon_0} = 3$ and permeability $\mu = 2\mu_0$.
Hence speed in the medium is
$$ v = \frac{1}{\sqrt{(2\mu_0)(3\epsilon_0)}} = \frac{1}{\sqrt{6\mu_0\epsilon_0}} $$
Now the ratio of speeds in vacuum and the medium is
$$ \frac{v_0}{v} = \sqrt{6} $$
Therefore,
$$ v_0 : v = \sqrt{6} : 1 $$
Updated for JEE Main 2026: This PYQ is important for JEE Mains, JEE Advanced and other competitive exams. Practice more questions from this chapter.