For a fixed amount of gas, the combined gas law is given by
$$ \frac{P_1 V_1}{T_1} = \frac{P_2 V_2}{T_2} $$
Initial conditions:
$$ P_1 = 2\ \text{atm}, \quad V_1 = 60\ \text{cm}^3, \quad T_1 = 27^\circ\text{C} = 300\ \text{K} $$
Final conditions:
$$ V_2 = 20\ \text{cm}^3, \quad T_2 = 77^\circ\text{C} = 350\ \text{K} $$
Substituting into the equation,
$$ \frac{2 \times 60}{300} = \frac{P_2 \times 20}{350} $$
$$ \frac{120}{300} = \frac{20P_2}{350} $$
$$ \frac{2}{5} = \frac{2P_2}{35} $$
$$ P_2 = 7\ \text{atm} $$
Hence, the final pressure of the gas is
7 atmospheric pressure.
Updated for JEE Main 2026: This PYQ is important for JEE Mains, JEE Advanced and other competitive exams. Practice more questions from this chapter.