Root mean square speed is given by:
\[ v_{rms} = \sqrt{\frac{3kT}{m}} \]
Since the r.m.s. speeds are equal,
\[ \sqrt{\frac{3kT_1}{m_1}} = \sqrt{\frac{3kT_2}{m_2}} \]
Squaring both sides:
\[ \frac{T_1}{m_1} = \frac{T_2}{m_2} \]
Given:
Temperature of oxygen = 47 °C = 320 K
Mass ratio:
\[ \frac{m_{O_2}}{m_{H_2}} = \frac{32}{2} = 16 \]
Thus,
\[ \frac{320}{m_{O_2}} = \frac{T_2}{m_{H_2}} \]
\[ T_2 = 320 \times \frac{m_{H_2}}{m_{O_2}} \]
\[ T_2 = 320 \times \frac{1}{16} \]
\[ T_2 = 20 K \]
Convert to °C:
\[ T = 20 - 273 \]
\[ T = -253 °C \]
Hence hydrogen must be kept at -253 °C.
Updated for JEE Main 2026: This PYQ is important for JEE Mains, JEE Advanced and other competitive exams. Practice more questions from this chapter.