Q. 0.01 mole of an organic compound (X) containing 10% hydrogen, on complete combustion produced 0.9 g of H₂O. Molar mass of (X) is ______ g mol⁻¹.
Step 1: Mass of water produced = 0.9 g
Moles of H₂O = 0.9 / 18 = 0.05 mol
Step 2:
1 mole of H₂O contains 2 moles of H
Moles of H = 0.05 × 2 = 0.10 mol
Step 3:
Mass of H = 0.10 × 1 = 0.10 g
Step 4:
Given hydrogen is 10% by mass
So total mass of compound = (0.10 × 100) / 10 = 1.0 g
Step 5:
0.01 mole of compound has mass = 1.0 g
Molar mass = 1.0 / 0.01 = 100 g mol⁻¹
✔ Final Answer: 100 g mol⁻¹