(A) 1.83
(B) 2.0
(C) 5.5
(D) 18.3
The intensity of an electromagnetic wave is given by the relation
$$ I = \frac{1}{2} c \varepsilon_0 E_0^2 $$
where $E_0$ is the amplitude of the electric field.
Rearranging the formula,
$$ E_0 = \sqrt{\frac{2I}{c\varepsilon_0}} $$
Substitute the given values,
$$ E_0 = \sqrt{\frac{2 \times 4.0 \times 10^{14}}{3 \times 10^8 \times 8.85 \times 10^{-12}}} $$
$$ E_0 = \sqrt{\frac{8.0 \times 10^{14}}{2.655 \times 10^{-3}}} $$
$$ E_0 = \sqrt{3.01 \times 10^{17}} $$
$$ E_0 \approx 5.48 \times 10^8\ \text{V/m} $$
For an electromagnetic wave, the relation between electric and magnetic field amplitudes is
$$ E_0 = c B_0 $$
So,
$$ B_0 = \frac{E_0}{c} $$
$$ B_0 = \frac{5.48 \times 10^8}{3 \times 10^8} $$
$$ B_0 \approx 1.83\ \text{T} $$
Hence, the amplitude of magnetic field is
1.83 T
Updated for JEE Main 2026: This PYQ is important for JEE Mains, JEE Advanced and other competitive exams. Practice more questions from this chapter.