Sucrose Hydrolysis and Optical Rotation | JEE Main 2026 Chemistry
Given below are two statements :

Statement I : Sucrose is dextrorotatory. However, sucrose upon hydrolysis gives a solution having mixture of products. This solution shows laevorotation.

Statement II : Hydrolysis of sucrose gives glucose and fructose. Since the laevorotation of glucose is more than the dextrorotation of fructose, the resulting solution becomes laevorotatory.

In the light of the above statements, choose the correct answer from the options given below :
A. Both Statement I and Statement II are false
B. Both Statement I and Statement II are true
C. Statement I is true but Statement II is false
D. Statement I is false but Statement II is true
Correct Answer: Statement I is true but Statement II is false

Detailed Explanation

Sucrose is a dextrorotatory disaccharide.

On hydrolysis, sucrose breaks into an equimolar mixture of:

• D-(+)-glucose (dextrorotatory)
• D-(−)-fructose (laevorotatory)


The magnitude of optical rotation:

| rotation of fructose | > | rotation of glucose |

Since fructose has a much higher laevorotation compared to the dextrorotation of glucose, the net rotation of the mixture becomes laevorotatory.

This hydrolysed solution is called invert sugar.


Statement I:

Sucrose is dextrorotatory, but its hydrolysis product is laevorotatory due to dominance of fructose.

✔ Statement I is true.


Statement II:

The statement wrongly claims that laevorotation of glucose is more than dextrorotation of fructose.

This is incorrect because:

| fructose rotation | > | glucose rotation |

✘ Statement II is false.


Hence, the correct answer is:

Statement I is true but Statement II is false

This concept is very important for JEE Main, JEE Advanced and IIT JEE optical activity questions.

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Updated for JEE Main 2026: This PYQ is important for JEE Mains, JEE Advanced and other competitive exams. Practice more questions from this chapter.

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