Explanation (Complete Step-by-Step)

For an isobaric process:

\[ W = P\Delta V = nR\Delta T \]

Heat supplied in isobaric process is:

\[ Q = nC_p \Delta T \]

Now,

\[ \gamma = \frac{C_p}{C_v} \]

Also,

\[ C_p - C_v = R \]

From \( \gamma = 1.4 \):

\[ C_p = \frac{\gamma R}{\gamma - 1} \]

\[ C_p = \frac{1.4R}{0.4} \]

\[ C_p = 3.5R \]

Now,

\[ W = nR\Delta T = 100 \]

\[ Q = nC_p \Delta T \]

\[ Q = n(3.5R)\Delta T \]

\[ Q = 3.5(nR\Delta T) \]

\[ Q = 3.5W \]

\[ Q = 3.5 \times 100 \]

\[ Q = 350 \text{ J} \]

Therefore, heat given to the gas = 350 J

Related JEE Main Questions